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Arrays in C

Minimum in array

C Program: Minimum in array

Method 1: Using for loop

C 
#include <stdio.h>


 


int main() {


    int arr[100], n, i, min;


 


    // Input number of elements


    printf("Enter number of elements: ");


    scanf("%d", &n);


 


    // Input array elements


    printf("Enter %d elements:\n", n);


    for(i = 0; i < n; i++) {


        scanf("%d", &arr[i]);


    }


 


    // Assume first element as minimum


    min = arr[0];


 


    // Find minimum element using for loop


    for(i = 1; i < n; i++) {


        if(arr[i] < min) {


            min = arr[i];


        }


    }


 


    // Display result


    printf("\nMinimum element in the array = %d\n", min);


 


    return 0;


}

Output

 
INPUT :
Enter number of elements: 6
Enter 6 elements:
45 12 78 5 33 19


OUTPUT :
Minimum element in the array = 5

Explanation

  1. The user inputs the total number of elements (n).
  2. A for loop reads each array element.
  3. The program assumes the first element as the minimum (min = arr[0]).
  4. The next for loop traverses all elements and updates min whenever a smaller element is found.
  5. Finally, it prints the minimum element in the array.

 

C Program: Minimum in array

Method 2: Using while loop

C 
#include <stdio.h>


 


int main() {


    int arr[100], n, i = 0, min;


 


    // Input number of elements


    printf("Enter number of elements: ");


    scanf("%d", &n);


 


    // Input array elements


    printf("Enter %d elements:\n", n);


    while(i < n) {


        scanf("%d", &arr[i]);


        i++;


    }


 


    // Initialize minimum with first element


    min = arr[0];


 


    // Reset index for comparison


    i = 1;


 


    // Find minimum element using while loop


    while(i < n) {


        if(arr[i] < min) {


            min = arr[i];


        }


        i++;


    }


 


    // Display result


    printf("\nMinimum element in the array = %d\n", min);


 


    return 0;


}

Output

 
INPUT :
Enter number of elements: 5
Enter 5 elements:
12 45 8 67 3

OUTPUT :
Minimum element in the array = 3

Explanation

  1. The program first asks the user to input the number of elements (n).
  2. Using a while loop, it reads all n elements into the array.
  3. It initializes min with the first array element (arr[0]).
  4. Another while loop is used to compare each element with min.
    • If a smaller element is found, min is updated.
  5. After the loop ends, the smallest element is printed.

 

C Program: Minimum in array

Method 3: Using do..while loop

C 
#include <stdio.h>


 


int main() {


    int arr[100], n, i = 0, min;


 


    // Input number of elements


    printf("Enter number of elements: ");


    scanf("%d", &n);


 


    // Input array elements using do...while loop


    printf("Enter %d elements:\n", n);


    do {


        scanf("%d", &arr[i]);


        i++;


    } while(i < n);


 


    // Assume first element as minimum


    min = arr[0];


 


    // Find minimum element using do...while loop


    i = 1;


    do {


        if(arr[i] < min) {


            min = arr[i];


        }


        i++;


    } while(i < n);


 


    // Display result


    printf("\nMinimum element in the array = %d\n", min);


 


    return 0;


}

Output

 
INPUT :
Enter number of elements: 5
Enter 5 elements:
34 12 56 7 23

OUTPUT :
Minimum element in the array = 7

Explanation

  1. The user enters how many elements (n) the array should have.
  2. Using a dodo..while loop, all elements are read into the array.
  3. The first element is assumed as the minimum (min = arr[0]).
  4. Another do..while loop traverses the array from the second element onward.
    • If a smaller value is found, it updates min.
  5. Finally, it prints the minimum element.

 

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