C Programs

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Decision Making Programs in C

Check whether a year is a Leap Year

Introduction

A leap year has 366 days instead of 365, with February 29 as the extra day.

Rules to check a leap year:

1. If a year is divisible by 4 → it might be a leap year
2. If the year is divisible by 100 → it is not a leap year, unless
3. The year is also divisible by 400 → it is a leap year

Examples:

• 2020 → Leap Year (divisible by 4, not by 100)
• 1900 → Not a Leap Year (divisible by 100, not by 400)
• 2000 → Leap Year (divisible by 400)

C Program: Check whether a year is a Leap Year

#include <stdio.h>
 
int main() {
    int year;
 
    // Input year from user
    printf("Enter a year: ");
    scanf("%d", &year);
 
    // Check leap year conditions
    if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
        printf("%d is a Leap Year.\n", year);
    } else {
        printf("%d is not a Leap Year.\n", year);
    }
 
    return 0;
}

 
OUTPUT 1 :
Enter a year: 2024
2024 is a Leap Year.

OUTPUT 2 :
Enter a year: 1900
1900 is not a Leap Year.


OUTPUT 3 :
Enter a year: 2000
2000 is a Leap Year.
 

Explanation

1. User enters a year.
2. Condition checks:
   • (year % 4 == 0 && year % 100 != 0) → divisible by 4 but not by 100
   • (year % 400 == 0) → divisible by 400
3. If either condition is true → Leap Year
4. Else → Not a Leap Year