C Programs

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Menu-Driven Number Check of Positive, Negative, or Zero and Even or Odd

Introduction

Menu-driven programs are very useful in real-world applications where the user chooses what task to perform.
Here, we’ll use a switch-case to provide options for number checking.

Menu-driven program in C where the user can choose what they want to check:

Check Positive/Negative/Zero
Check Even/Odd
Check Both
Exit

C Program: Menu-Driven Number Check of Positive, Negative, or Zero and Even or Odd

#include <stdio.h>
 
int main() {
    int num, choice;
 
    do {
        // Display menu
        printf("\n===== Number Checking Menu =====\n");
        printf("1. Check Positive/Negative/Zero\n");
        printf("2. Check Even/Odd\n");
        printf("3. Check Both (Sign and Even/Odd)\n");
        printf("4. Exit\n");
        printf("Enter your choice: ");
        scanf("%d", &choice);
 
        if (choice == 4) {
            printf("Exiting program. Goodbye!\n");
            break;
        }
 
        // Input number only if choice is valid
        printf("Enter a number: ");
        scanf("%d", &num);
 
        switch (choice) {
            case 1:
                if (num > 0)
                    printf("%d is Positive.\n", num);
                else if (num < 0)
                    printf("%d is Negative.\n", num);
                else
                    printf("The number is Zero.\n");
                break;
 
            case 2:
                if (num == 0) {
                    printf("The number is Zero (neither Even nor Odd).\n");
                } else if (num % 2 == 0)
                    printf("%d is Even.\n", num);
                else
                    printf("%d is Odd.\n", num);
                break;
 
            case 3:
                if (num == 0) {
                    printf("The number is Zero (neither Positive/Negative nor Even/Odd).\n");
                } else {
                    if (num > 0)
                        printf("%d is Positive and ", num);
                    else
                        printf("%d is Negative and ", num);
 
                    if (num % 2 == 0)
                        printf("Even.\n");
                    else
                        printf("Odd.\n");
                }
                break;
 
            default:
                printf("Invalid choice! Please enter 1–4.\n");
        }
 
    } while (choice != 4);
 
    return 0;
}

Output

 
OUTPUT :
===== Number Checking Menu =====
1. Check Positive/Negative/Zero
2. Check Even/Odd
3. Check Both (Sign and Even/Odd)
4. Exit
Enter your choice: 3
Enter a number: -8
-8 is Negative and Even.

===== Number Checking Menu =====
1. Check Positive/Negative/Zero
2. Check Even/Odd
3. Check Both (Sign and Even/Odd)
4. Exit
Enter your choice: 2
Enter a number: 0
The number is Zero (neither Even nor Odd).

===== Number Checking Menu =====
1. Check Positive/Negative/Zero
2. Check Even/Odd
3. Check Both (Sign and Even/Odd)
4. Exit
Enter your choice: 4
Exiting program. Goodbye!

Explanation

Program shows a menu repeatedly using a ..while loop.
switch-case handles user’s choice.
User enters a number → program checks conditions.
Option 4 exits the loop and program ends.

Basics of C Programming (Introductory Programs)

Control Statements & Loops in C

Functions

Arrays

Strings

Pointers

Structures and Unions

Dynamic Memory Allocation

File Handling

Data Structures in C

Advanced C Programs

User-Defined Number Programs in C

User-Defined String Programs in C