Conditional Constructs in Java

Chapter 8

Conditional Constructs in Java

Class 10 - Logix Kips ICSE Computer Applications with BlueJ

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Java Program: Pythagorean Triplet Checker

33. Write a program in Java to accept three numbers and check whether they are Pythagorean Triplet or not. The program must display the message accordingly. [Hint: h²=p²+b²]

📐 Concept

Three numbers form a Pythagorean Triplet if:

h²=p²+b²

Where:

h = largest number (hypotenuse)
p, b = the other two numbers

Example:
3, 4, 5 → 5² = 3² + 4²

Java

import java.util.Scanner;
 
public class PythagoreanTriplet {
    public static void main(String[] args) {
 
        // Title
        System.out.println("PYTHAGOREAN TRIPLET CHECKER");
        System.out.println("---------------------------");
 
        Scanner sc = new Scanner(System.in);
 
        int a, b, c;
        int h, p, base;
 
        System.out.print("Enter first number: ");
        a = sc.nextInt();
 
        System.out.print("Enter second number: ");
        b = sc.nextInt();
 
        System.out.print("Enter third number: ");
        c = sc.nextInt();
 
        // Finding the largest number (hypotenuse)
        if (a >= b && a >= c) {
            h = a;
            p = b;
            base = c;
        } else if (b >= a && b >= c) {
            h = b;
            p = a;
            base = c;
        } else {
            h = c;
            p = a;
            base = b;
        }
 
        // Check Pythagorean condition
        if (h * h == (p * p + base * base))
            System.out.println("The given numbers form a Pythagorean Triplet.");
        else
            System.out.println("The given numbers do NOT form a Pythagorean Triplet.");
 
        sc.close();
    }
}

Output

Sample Run 1 

Enter first number: 3
Enter second number: 4
Enter third number: 5
The given numbers form a Pythagorean Triplet.

Sample Run 2 
Enter first number: 5
Enter second number: 6
Enter third number: 7
The given numbers do NOT form a Pythagorean Triplet.

📝 Explanation

Program accepts three integers
Finds the largest number and assumes it as the hypotenuse
Squares all values and checks:

h² = p² + b²

Displays result accordingly